src/libimcv/imv/imv_lang_string.c

   1 /*
   2  * Copyright (C) 2012 Andreas Steffen
   3  * HSR Hochschule fuer Technik Rapperswil
   4  *
   5  * This program is free software; you can redistribute it and/or modify it
   6  * under the terms of the GNU General Public License as published by the
   7  * Free Software Foundation; either version 2 of the License, or (at your
   8  * option) any later version.  See <http://www.fsf.org/copyleft/gpl.txt>.
   9  *
  10  * This program is distributed in the hope that it will be useful, but
  11  * WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY
  12  * or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License
  13  * for more details.
  14  */
  15
  16 #include "imv_lang_string.h"
  17
  18 #include <utils/debug.h>
  19
  20 /**
  21  * Described in header.
  22  */
  23 char* imv_lang_string_select_lang(enumerator_t *language_enumerator,
  24                                                                   char* languages[], int lang_count)
  25 {
  26         bool match = FALSE;
  27         char *lang;
  28         int i, i_chosen = 0;
  29
  30         while (language_enumerator->enumerate(language_enumerator, &lang))
  31         {
  32                 for (i = 0; i < lang_count; i++)
  33                 {
  34                         if (streq(lang, languages[i]))
  35                         {
  36                                 match = TRUE;
  37                                 i_chosen = i;
  38                                 break;
  39                         }
  40                 }
  41                 if (match)
  42                 {
  43                         break;
  44                 }
  45         }
  46         return languages[i_chosen];
  47 }
  48
  49 /**
  50  * Described in header.
  51  */
  52 char* imv_lang_string_select_string(imv_lang_string_t lang_string[], char *lang)
  53 {
  54         char *string;
  55         int i = 0;
  56
  57         if (!lang_string)
  58         {
  59                 return NULL;
  60         }
  61
  62         string = lang_string[0].string;
  63         while (lang_string[i].lang)
  64         {
  65                 if (streq(lang, lang_string[i].lang))
  66                 {
  67                         string = lang_string[i].string;
  68                         break;
  69                 }
  70                 i++;
  71         }
  72         return string;
  73 }